The quantitative relationship between chemical substances in a reaction is known as **stoichiometry**. Avogadro was a pioneer in this field of chemistry. Avogadro hypothesized that there was a specific number that would represent the number of atoms or molecules in a **mole** of that atom or molecule. The weight of that unit known as a **mole** would be equivalent to the atomic or molecular weight of the atom or molecule in grams. According to this theory, one mole of carbon-12 would have a mass of 12 grams because carbon-12 has an atomic weight of 12 (6 neutrons and 6 protons). One mole of hydrogen would weigh one gram and would contain the same number of atoms as one mole of carbon. The magical number was, in fact, discovered to be 6.024E^{23}. It was named the **Avogadro Number** in honor of the father of stoichiometry even though he did not actually determine the exact number. The modern definition of a mole is as follows:

Exactly one mole represents the number of carbon atoms in exactly 12 grams of the carbon-12 isotope.

For an atom a mole represents 6.02E^{23} atoms. For a molecular compound, one mole represents 6.02E^{23} molecules. One could even take it to extremes and say that one mole of bananas is equal to 6.02E^{23} bananas.

Now you might ask, "what relevance does the Avogadro number have for me?" The answer is, just about everything when you are working in a chemistry lab. On the other hand, it is totally useless as a unit of measure for bananas.

One atom or even ten atoms are too small for an individual to measure out in a lab. A mole of a substance equals the **gram-formula mass** or the **gram-molar mass**. This equals the sum of all of the masses of all the elements in the formula of the substance. Basically, if one were to count all of the carbon atoms in one one mole of carbon-12, there would be 6.02E^{23} atoms and it would weigh 12 grams (remember the atomic weight of carbon is 12).

Using the information above, it is possible to calculate concentrations of solutions and make up solutions of desired concentration. It is also possible to use this information to determine how much of a given base would be needed in order to neutralize a specific acid and reach a pH of 7.

There are five units of concentration that are particularly useful to chemists. The first three: molality, molarity and normality are dependant upon the mole unit. The last two: percent by volume and percent by weight have nothing to do with mole, only weight or volume of the **solute** or substance to be diluted, versus the weight or volume of the **solvent** or substance in which the solute is diluted. Percentages can also be determined for solids within solids.

**Molality:** The molal unit is not used nearly as frequently as the molar unit. **A molality is the number of moles of solute dissolved in one kilogram of solvent**. Be careful not to confuse molality and molarity. Molality is represented by a small "m," whereas molarity is represented by an upper case "M." Note that the solvent must be weighed unless it is water. One liter of water has a specific gravity of 1.0 and weighs one kilogram; so one can measure out one liter of water and add the solute to it. Most other solvents have a specific gravity greater than or less than one. Therefore, one liter of anything other than water is not likely to occupy a liter of space. To make a one molal aqueous (water) solution of sodium chloride (NaCl) , measure out one kilogram of water and add one mole of the solute, NaCl to it. The atomic weight of sodium is 23 and the atomic weight of chlorine is 35. Therefore the formula weight for NaCl is 58, and 58 grams of NaCl dissolved in 1kg water would result in a 1 molal solution of NaCl.

**Molarity:** The molar unit is probably the most commonly used chemical unit of measurement. **Molarity is the number of moles of a solute dissolved in a liter of solution**. A molar solution of sodium chloride is made by placing 1 mole of a solute into a 1-liter volumetric flask. (Taking data from the example above we will use 58 grams of sodium chloride). Water is then added to the volumetric flask up to the one liter line. The result is a one molar solution of sodium chloride.

**Normality:** There is a relationship between normality and molarity. Normality can only be calculated when we deal with reactions, because normality is a function of equivalents.

The example below uses potassium hydroxide (KOH) to neutralize arsenic acid. By studying the reaction it is possible to determine the proton exchange number to determine the normality of the arsenic acid.

Look at the equation H_{3}AsO_{4} + 2KOH --> K_{2}HAsO_{4} + 2H_{2}O:

Equivalent weight = molar mass/(H+ per mole)

Equivalent = mass of compound / Equivalent weight

And Normality = (equivalents of X)/Liter

And the part that is of interest to you is that Normality = molarity x n (where n = the number of protons exchanged in a reaction).

You probably remember that when a hydrogen atom is ionized and loses its electron, you are left with only a proton. So a hydrogen ion is basically a proton.

Let's assume that we have a 0.25 M solution of H_{3}AsO_{4} and want to determine the normality of it if it participates in the reaction

H_{3}AsO_{4} + 2KOH --> K_{2}HAsO_{4} + 2H_{2}O

When H_{3}AsO_{4} is neutralized by KOH, H_{3}AsO_{4} provides two protons to form 2H_{2}O.

Note that H_{3}AsO_{4} has three hydrogens, but K_{2}HAsO_{4} only has one hydrogen. That means that 2 protons were exchanged,

Again normality = molarity * n

Remember that normality of the solution is 0.25 mol H_{3}AsO_{4} and there were two protons exchanged (2 equivalents/mole)

So, in short, while there is a relationship between the normality of a solution and the molarity of a solution, the normality can only be determined by examining reaction, determining the proton exchange and multiplying molarity by that number.

Normality is particularly useful in titrations calculations.

- Where N = normality, V = volume, a = the substance on the left of the equation involved in proton exchange, and b=substance on the right of the equation involved in proton exchange:
- NaVa = NbVb

**Percent by weight:** To make up a solution based on percentage by weight, one would simply determine what percentage was desired (for example, a 20% by weight aqueous solution of sodium chloride) and the total quantity to be prepared.

- If the total quantity needed is 1 kg, then it would simply be a matter of calculating 20% of 1 kg which, of course is:
- 0.20 NaCl * 1000 g/kg = 200 g NaCl/kg.

**Percent by volume:** Solutions based on percent by volume are calculated the same as for percent by weight, except that calculations are based on volume. Thus one would simply determine what percentage was desired (for example, a 20% by volume aqueous solution of sodium chloride) and the total quantity to be prepared.

- If the total quantity needed is 1 liter, then it would simply be a matter of calculating 20% of 1 liter which, of course is:
- 0.20 NaCl * 1000 ml/l = 200 ml NaCl/l.

Percentages are used more in the technological fields of chemistry (such as environmental technologies) than they are in pure chemistry.

[Last updated: 2006-01-12: corrections]

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Provides comprehensive data on the chemical elements including scores of properties, element names in many languages, chemical compounds, most known nuclides. - Anatomy of the Atom

Answers many questions regarding the structure of atoms.

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